Base | Representation |
---|---|
bin | 1010110101011011011000… |
… | …1110001011101001011111 |
3 | 1120011212112120000112002111 |
4 | 2231112312032023221133 |
5 | 3030140311334422342 |
6 | 41200431325534451 |
7 | 2336454165555553 |
oct | 255266616135137 |
9 | 46155476015074 |
10 | 11913001482847 |
11 | 3883303847253 |
12 | 14049a0114427 |
13 | 685511680a7a |
14 | 2d2841591863 |
15 | 159d4032c217 |
hex | ad5b638ba5f |
11913001482847 has 2 divisors, whose sum is σ = 11913001482848. Its totient is φ = 11913001482846.
The previous prime is 11913001482829. The next prime is 11913001482883. The reversal of 11913001482847 is 74828410031911.
It is a weak prime.
It is an emirp because it is prime and its reverse (74828410031911) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11913001482847 - 27 = 11913001482719 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11913001482847.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11913001482047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5956500741423 + 5956500741424.
It is an arithmetic number, because the mean of its divisors is an integer number (5956500741424).
Almost surely, 211913001482847 is an apocalyptic number.
11913001482847 is a deficient number, since it is larger than the sum of its proper divisors (1).
11913001482847 is an equidigital number, since it uses as much as digits as its factorization.
11913001482847 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 387072, while the sum is 49.
The spelling of 11913001482847 in words is "eleven trillion, nine hundred thirteen billion, one million, four hundred eighty-two thousand, eight hundred forty-seven".
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