119203839553 has 4 divisors (see below), whose sum is σ = 119204530308. Its totient is φ = 119203148800.

The previous prime is 119203839533. The next prime is 119203839589. The reversal of 119203839553 is 355938302911.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 5262486849 + 113941352704 = 72543^2 + 337552^2 .

It is a cyclic number.

It is not a de Polignac number, because 119203839553 - 2²⁵ = 119170285121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 119203839497 and 119203839506.

It is not an unprimeable number, because it can be changed into a prime (119203839523) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159153 + ... + 513553.

It is an arithmetic number, because the mean of its divisors is an integer number (29801132577).

Almost surely, 2^119203839553 is an apocalyptic number.

It is an amenable number.

119203839553 is a deficient number, since it is larger than the sum of its proper divisors (690755).

119203839553 is an equidigital number, since it uses as much as digits as its factorization.

119203839553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 690754.

The product of its (nonzero) digits is 874800, while the sum is 49.

The spelling of 119203839553 in words is "one hundred nineteen billion, two hundred three million, eight hundred thirty-nine thousand, five hundred fifty-three".