Base | Representation |
---|---|
bin | 10110001110100001… |
… | …11100000000001001 |
3 | 1010210122010021101111 |
4 | 23013100330000021 |
5 | 143414324300044 |
6 | 5252034250321 |
7 | 601466112655 |
oct | 130720740011 |
9 | 33718107344 |
10 | 11933040649 |
11 | 5073988072 |
12 | 23904269a1 |
13 | 118231bcca |
14 | 812b8ba65 |
15 | 49c945b34 |
hex | 2c743c009 |
11933040649 has 4 divisors (see below), whose sum is σ = 12561095440. Its totient is φ = 11304985860.
The previous prime is 11933040643. The next prime is 11933040661. The reversal of 11933040649 is 94604033911.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11933040649 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11933040643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 314027367 + ... + 314027404.
It is an arithmetic number, because the mean of its divisors is an integer number (3140273860).
Almost surely, 211933040649 is an apocalyptic number.
11933040649 is a gapful number since it is divisible by the number (19) formed by its first and last digit.
It is an amenable number.
11933040649 is a deficient number, since it is larger than the sum of its proper divisors (628054791).
11933040649 is an equidigital number, since it uses as much as digits as its factorization.
11933040649 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 628054790.
The product of its (nonzero) digits is 69984, while the sum is 40.
The spelling of 11933040649 in words is "eleven billion, nine hundred thirty-three million, forty thousand, six hundred forty-nine".
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