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11936437779913 is a prime number
BaseRepresentation
bin1010110110110010101100…
…1000100011110111001001
31120021010000212112202201221
42231230223020203313021
53031031311032424123
641215305051042041
72341244025033343
oct255545310436711
946233025482657
1011936437779913
11389223aa430a9
121409440a40321
136877a7c4c77a
142d3a25db2293
1515a762ac025d
hexadb2b223dc9

11936437779913 has 2 divisors, whose sum is σ = 11936437779914. Its totient is φ = 11936437779912.

The previous prime is 11936437779829. The next prime is 11936437779919. The reversal of 11936437779913 is 31997773463911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8665505100729 + 3270932679184 = 2943723^2 + 1808572^2 .

It is an emirp because it is prime and its reverse (31997773463911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11936437779913 - 221 = 11936435682761 is a prime.

It is not a weakly prime, because it can be changed into another prime (11936437779919) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5968218889956 + 5968218889957.

It is an arithmetic number, because the mean of its divisors is an integer number (5968218889957).

Almost surely, 211936437779913 is an apocalyptic number.

It is an amenable number.

11936437779913 is a deficient number, since it is larger than the sum of its proper divisors (1).

11936437779913 is an equidigital number, since it uses as much as digits as its factorization.

11936437779913 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 162030456, while the sum is 70.

The spelling of 11936437779913 in words is "eleven trillion, nine hundred thirty-six billion, four hundred thirty-seven million, seven hundred seventy-nine thousand, nine hundred thirteen".