Base | Representation |
---|---|
bin | 10110001111010000… |
… | …00110110100101001 |
3 | 1010211001112211211211 |
4 | 23013220012310221 |
5 | 143422403124111 |
6 | 5252412353121 |
7 | 601601540233 |
oct | 130750066451 |
9 | 33731484754 |
10 | 11939114281 |
11 | 50773562a6 |
12 | 23924757a1 |
13 | 1183667683 |
14 | 8138cd253 |
15 | 49d245521 |
hex | 2c7a06d29 |
11939114281 has 2 divisors, whose sum is σ = 11939114282. Its totient is φ = 11939114280.
The previous prime is 11939114279. The next prime is 11939114311. The reversal of 11939114281 is 18241193911.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11633563881 + 305550400 = 107859^2 + 17480^2 .
It is a cyclic number.
It is not a de Polignac number, because 11939114281 - 21 = 11939114279 is a prime.
It is a super-2 number, since 2×119391142812 (a number of 21 digits) contains 22 as substring.
Together with 11939114279, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11939114381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5969557140 + 5969557141.
It is an arithmetic number, because the mean of its divisors is an integer number (5969557141).
Almost surely, 211939114281 is an apocalyptic number.
It is an amenable number.
11939114281 is a deficient number, since it is larger than the sum of its proper divisors (1).
11939114281 is an equidigital number, since it uses as much as digits as its factorization.
11939114281 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15552, while the sum is 40.
The spelling of 11939114281 in words is "eleven billion, nine hundred thirty-nine million, one hundred fourteen thousand, two hundred eighty-one".
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