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11941842977 is a prime number
BaseRepresentation
bin10110001111100101…
…00001000000100001
31010211020200110220122
423013302201000201
5143424102433402
65252551050025
7601633663511
oct130762410041
933736613818
1011941842977
11507894a419
122393370915
1311840b169c
14813ddd841
1549d5d3ca2
hex2c7ca1021

11941842977 has 2 divisors, whose sum is σ = 11941842978. Its totient is φ = 11941842976.

The previous prime is 11941842943. The next prime is 11941843009. The reversal of 11941842977 is 77924814911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8992918561 + 2948924416 = 94831^2 + 54304^2 .

It is a cyclic number.

It is not a de Polignac number, because 11941842977 - 232 = 7646875681 is a prime.

It is a super-2 number, since 2×119418429772 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11941844977) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5970921488 + 5970921489.

It is an arithmetic number, because the mean of its divisors is an integer number (5970921489).

Almost surely, 211941842977 is an apocalyptic number.

It is an amenable number.

11941842977 is a deficient number, since it is larger than the sum of its proper divisors (1).

11941842977 is an equidigital number, since it uses as much as digits as its factorization.

11941842977 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1016064, while the sum is 53.

The spelling of 11941842977 in words is "eleven billion, nine hundred forty-one million, eight hundred forty-two thousand, nine hundred seventy-seven".