Base | Representation |
---|---|
bin | 1010110111001110100001… |
… | …0110101101010001100011 |
3 | 1120021211022102212020001012 |
4 | 2231303220112231101203 |
5 | 3031142110240141403 |
6 | 41222542201531135 |
7 | 2341630105236425 |
oct | 255635026552143 |
9 | 46254272766035 |
10 | 11943907349603 |
11 | 389542335a399 |
12 | 140a9864a3aab |
13 | 6883c86149a8 |
14 | 2d4134042815 |
15 | 15aa4d740ed8 |
hex | adce85ad463 |
11943907349603 has 8 divisors (see below), whose sum is σ = 12007736057856. Its totient is φ = 11880092133000.
The previous prime is 11943907349551. The next prime is 11943907349611. The reversal of 11943907349603 is 30694370934911.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11943907349603 - 218 = 11943907087459 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11943907349303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1595123 + ... + 5141228.
It is an arithmetic number, because the mean of its divisors is an integer number (1500967007232).
Almost surely, 211943907349603 is an apocalyptic number.
11943907349603 is a deficient number, since it is larger than the sum of its proper divisors (63828708253).
11943907349603 is an equidigital number, since it uses as much as digits as its factorization.
11943907349603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6745825.
The product of its (nonzero) digits is 13226976, while the sum is 59.
The spelling of 11943907349603 in words is "eleven trillion, nine hundred forty-three billion, nine hundred seven million, three hundred forty-nine thousand, six hundred three".
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