11953407316900 has 81 divisors (see below), whose sum is σ = 30174426256737. Its totient is φ = 4098228103200.

The previous prime is 11953407316867. The next prime is 11953407316913. The reversal of 11953407316900 is 961370435911.

The square root of 11953407316900 is 3457370.

It is a perfect power (a square), and thus also a powerful number.

It can be written as a sum of positive squares in only one way, i.e., 4303226634084 + 7650180682816 = 2074422^2 + 2765896^2 .

It is a super-2 number, since 2×11953407316900² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (49).

It is an unprimeable number.

It is a polite number, since it can be written in 26 ways as a sum of consecutive naturals, for example, 241991205 + ... + 242040595.

Almost surely, 2^{11953407316900} is an apocalyptic number.

11953407316900 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11953407316900 is the 3457370-th square number.

It is an amenable number.

11953407316900 is an abundant number, since it is smaller than the sum of its proper divisors (18221018939837).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11953407316900 is an frugal number, since it uses more digits than its factorization.

11953407316900 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 98810 (or 49405 counting only the distinct ones).

The product of its (nonzero) digits is 612360, while the sum is 49.

Multiplying 11953407316900 by its sum of digits (49), we get a square (585716958528100 = 24201590²).

11953407316900 divided by its sum of digits (49) gives a square (243947088100 = 493910²).

The spelling of 11953407316900 in words is "eleven trillion, nine hundred fifty-three billion, four hundred seven million, three hundred sixteen thousand, nine hundred".