Base | Representation |
---|---|
bin | 101101101000… |
… | …101010100001 |
3 | 211111210012121 |
4 | 231220222201 |
5 | 11030304131 |
6 | 1104224241 |
7 | 203453446 |
oct | 55505241 |
9 | 24453177 |
10 | 11963041 |
11 | 6831012 |
12 | 400b081 |
13 | 262b22c |
14 | 18359cd |
15 | 10b4911 |
hex | b68aa1 |
11963041 has 2 divisors, whose sum is σ = 11963042. Its totient is φ = 11963040.
The previous prime is 11963023. The next prime is 11963047. The reversal of 11963041 is 14036911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7862416 + 4100625 = 2804^2 + 2025^2 .
It is a cyclic number.
It is not a de Polignac number, because 11963041 - 213 = 11954849 is a prime.
It is a super-2 number, since 2×119630412 = 286228699935362, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11962997 and 11963015.
It is not a weakly prime, because it can be changed into another prime (11963047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5981520 + 5981521.
It is an arithmetic number, because the mean of its divisors is an integer number (5981521).
Almost surely, 211963041 is an apocalyptic number.
It is an amenable number.
11963041 is a deficient number, since it is larger than the sum of its proper divisors (1).
11963041 is an equidigital number, since it uses as much as digits as its factorization.
11963041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
The square root of 11963041 is about 3458.7629291410. The cubic root of 11963041 is about 228.7075651624.
Adding to 11963041 its reverse (14036911), we get a palindrome (25999952).
The spelling of 11963041 in words is "eleven million, nine hundred sixty-three thousand, forty-one".
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