Base | Representation |
---|---|
bin | 10001011010001011100… |
… | …100011100011001111111 |
3 | 11020100222011110121010122 |
4 | 101122023210130121333 |
5 | 124100102134313342 |
6 | 2313331523325155 |
7 | 152301324264503 |
oct | 21321344343177 |
9 | 4210864417118 |
10 | 1196342494847 |
11 | 421403171365 |
12 | 173a388207bb |
13 | 88a78922386 |
14 | 41c9088a303 |
15 | 211bda6a4d2 |
hex | 1168b91c67f |
1196342494847 has 2 divisors, whose sum is σ = 1196342494848. Its totient is φ = 1196342494846.
The previous prime is 1196342494843. The next prime is 1196342494883. The reversal of 1196342494847 is 7484942436911.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1196342494847 - 22 = 1196342494843 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1196342494847.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1196342494843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 598171247423 + 598171247424.
It is an arithmetic number, because the mean of its divisors is an integer number (598171247424).
Almost surely, 21196342494847 is an apocalyptic number.
1196342494847 is a deficient number, since it is larger than the sum of its proper divisors (1).
1196342494847 is an equidigital number, since it uses as much as digits as its factorization.
1196342494847 is an evil number, because the sum of its binary digits is even.
The product of its digits is 41803776, while the sum is 62.
The spelling of 1196342494847 in words is "one trillion, one hundred ninety-six billion, three hundred forty-two million, four hundred ninety-four thousand, eight hundred forty-seven".
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