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11968980911869 is a prime number
BaseRepresentation
bin1010111000101011111011…
…0110110000011011111101
31120101020000212012011022111
42232022332312300123331
53032044433103134434
641242250211214021
72343505335062152
oct256127666603375
946336025164274
1011968980911869
1138a501a76a883
1214138035a7311
1368a893166277
142d5432098229
1515b519ae4964
hexae2bedb06fd

11968980911869 has 2 divisors, whose sum is σ = 11968980911870. Its totient is φ = 11968980911868.

The previous prime is 11968980911759. The next prime is 11968980911873. The reversal of 11968980911869 is 96811908986911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10510803909369 + 1458177002500 = 3242037^2 + 1207550^2 .

It is a cyclic number.

It is not a de Polignac number, because 11968980911869 - 215 = 11968980879101 is a prime.

It is a super-2 number, since 2×119689809118692 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11968980911795 and 11968980911804.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11968980971869) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5984490455934 + 5984490455935.

It is an arithmetic number, because the mean of its divisors is an integer number (5984490455935).

Almost surely, 211968980911869 is an apocalyptic number.

It is an amenable number.

11968980911869 is a deficient number, since it is larger than the sum of its proper divisors (1).

11968980911869 is an equidigital number, since it uses as much as digits as its factorization.

11968980911869 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120932352, while the sum is 76.

The spelling of 11968980911869 in words is "eleven trillion, nine hundred sixty-eight billion, nine hundred eighty million, nine hundred eleven thousand, eight hundred sixty-nine".