119743409 has 2 divisors, whose sum is σ = 119743410. Its totient is φ = 119743408.

The previous prime is 119743387. The next prime is 119743423. The reversal of 119743409 is 904347911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109662784 + 10080625 = 10472^2 + 3175^2 .

It is an emirp because it is prime and its reverse (904347911) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-119743409 is a prime.

It is a super-3 number, since 3×119743409³ (a number of 25 digits) contains 333 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (119743469) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59871704 + 59871705.

It is an arithmetic number, because the mean of its divisors is an integer number (59871705).

Almost surely, 2^119743409 is an apocalyptic number.

It is an amenable number.

119743409 is a deficient number, since it is larger than the sum of its proper divisors (1).

119743409 is an equidigital number, since it uses as much as digits as its factorization.

119743409 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27216, while the sum is 38.

The square root of 119743409 is about 10942.7331594990. The cubic root of 119743409 is about 492.8906040914.

The spelling of 119743409 in words is "one hundred nineteen million, seven hundred forty-three thousand, four hundred nine".