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11974655211193 is a prime number
BaseRepresentation
bin1010111001000001000100…
…0100011111011010111001
31120101202200022101102122201
42232100101010133122321
53032143043213224233
641245025231150201
72344066055606653
oct256202104373271
946352608342581
1011974655211193
1138a7471762954
121414927975361
1368b28890612c
142d580d9236d3
1515b74cd4377d
hexae41111f6b9

11974655211193 has 2 divisors, whose sum is σ = 11974655211194. Its totient is φ = 11974655211192.

The previous prime is 11974655211179. The next prime is 11974655211227. The reversal of 11974655211193 is 39111255647911.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11868762241449 + 105892969744 = 3445107^2 + 325412^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11974655211193 is a prime.

It is not a weakly prime, because it can be changed into another prime (11974655217193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5987327605596 + 5987327605597.

It is an arithmetic number, because the mean of its divisors is an integer number (5987327605597).

Almost surely, 211974655211193 is an apocalyptic number.

It is an amenable number.

11974655211193 is a deficient number, since it is larger than the sum of its proper divisors (1).

11974655211193 is an equidigital number, since it uses as much as digits as its factorization.

11974655211193 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2041200, while the sum is 55.

The spelling of 11974655211193 in words is "eleven trillion, nine hundred seventy-four billion, six hundred fifty-five million, two hundred eleven thousand, one hundred ninety-three".