1197750353 has 4 divisors (see below), whose sum is σ = 1202170368. Its totient is φ = 1193330340.

The previous prime is 1197750349. The next prime is 1197750361. The reversal of 1197750353 is 3530577911.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1197750353 - 2² = 1197750349 is a prime.

It is a super-4 number, since 4×1197750353⁴ (a number of 37 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1197750353.

It is not an unprimeable number, because it can be changed into a prime (1197750313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2209601 + ... + 2210142.

It is an arithmetic number, because the mean of its divisors is an integer number (300542592).

Almost surely, 2^1197750353 is an apocalyptic number.

It is an amenable number.

1197750353 is a deficient number, since it is larger than the sum of its proper divisors (4420015).

1197750353 is an equidigital number, since it uses as much as digits as its factorization.

1197750353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4420014.

The product of its (nonzero) digits is 99225, while the sum is 41.

The square root of 1197750353 is about 34608.5300612436. The cubic root of 1197750353 is about 1061.9940963729.

The spelling of 1197750353 in words is "one billion, one hundred ninety-seven million, seven hundred fifty thousand, three hundred fifty-three".