Base | Representation |
---|---|
bin | 10110010011111010… |
… | …01111011101111111 |
3 | 1010220210010001220222 |
4 | 23021331033131333 |
5 | 144012410143101 |
6 | 5300330331555 |
7 | 602555045366 |
oct | 131175173577 |
9 | 33823101828 |
10 | 11978209151 |
11 | 5097428907 |
12 | 23a3589bbb |
13 | 118b7a522c |
14 | 818b887dd |
15 | 4a18b901b |
hex | 2c9f4f77f |
11978209151 has 4 divisors (see below), whose sum is σ = 11981618472. Its totient is φ = 11974799832.
The previous prime is 11978209127. The next prime is 11978209189. The reversal of 11978209151 is 15190287911.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15190287911 = 83 ⋅183015517.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11978209151 is a prime.
It is a super-4 number, since 4×119782091514 (a number of 41 digits) contains 4444 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11978209651) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1699385 + ... + 1706418.
It is an arithmetic number, because the mean of its divisors is an integer number (2995404618).
Almost surely, 211978209151 is an apocalyptic number.
11978209151 is a deficient number, since it is larger than the sum of its proper divisors (3409321).
11978209151 is an equidigital number, since it uses as much as digits as its factorization.
11978209151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3409320.
The product of its (nonzero) digits is 45360, while the sum is 44.
The spelling of 11978209151 in words is "eleven billion, nine hundred seventy-eight million, two hundred nine thousand, one hundred fifty-one".
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