11979643 has 8 divisors (see below), whose sum is σ = 13145328. Its totient is φ = 10848864.

The previous prime is 11979631. The next prime is 11979647. The reversal of 11979643 is 34697911.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2^k-11979643 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11979596 and 11979605.

It is not an unprimeable number, because it can be changed into a prime (11979647) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8005 + ... + 9382.

It is an arithmetic number, because the mean of its divisors is an integer number (1643166).

Almost surely, 2^11979643 is an apocalyptic number.

11979643 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11979643 is a deficient number, since it is larger than the sum of its proper divisors (1165685).

11979643 is a wasteful number, since it uses less digits than its factorization.

11979643 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17453.

The product of its digits is 40824, while the sum is 40.

The square root of 11979643 is about 3461.1620880854. The cubic root of 11979643 is about 228.8133144138.

The spelling of 11979643 in words is "eleven million, nine hundred seventy-nine thousand, six hundred forty-three".