1198124143 has 2 divisors, whose sum is σ = 1198124144. Its totient is φ = 1198124142.

The previous prime is 1198124131. The next prime is 1198124159. The reversal of 1198124143 is 3414218911.

It is a weak prime.

It is an emirp because it is prime and its reverse (3414218911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1198124143 - 2⁵ = 1198124111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1198124099 and 1198124108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1198124843) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 599062071 + 599062072.

It is an arithmetic number, because the mean of its divisors is an integer number (599062072).

Almost surely, 2^1198124143 is an apocalyptic number.

1198124143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1198124143 is an equidigital number, since it uses as much as digits as its factorization.

1198124143 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 34.

The square root of 1198124143 is about 34613.9298982361. The cubic root of 1198124143 is about 1062.1045594271.

The spelling of 1198124143 in words is "one billion, one hundred ninety-eight million, one hundred twenty-four thousand, one hundred forty-three".