11983073 has 4 divisors (see below), whose sum is σ = 12238080. Its totient is φ = 11728068.

The previous prime is 11983067. The next prime is 11983099. The reversal of 11983073 is 37038911.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11983073 - 2⁴ = 11983057 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11983033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127433 + ... + 127526.

It is an arithmetic number, because the mean of its divisors is an integer number (3059520).

Almost surely, 2^11983073 is an apocalyptic number.

It is an amenable number.

11983073 is a deficient number, since it is larger than the sum of its proper divisors (255007).

11983073 is an equidigital number, since it uses as much as digits as its factorization.

11983073 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 255006.

The product of its (nonzero) digits is 4536, while the sum is 32.

The square root of 11983073 is about 3461.6575509429. The cubic root of 11983073 is about 228.8351502002.

The spelling of 11983073 in words is "eleven million, nine hundred eighty-three thousand, seventy-three".