Base | Representation |
---|---|
bin | 10110010100100001… |
… | …10010100001011111 |
3 | 1010221010202102011121 |
4 | 23022100302201133 |
5 | 144020213132341 |
6 | 5301032231411 |
7 | 602646440164 |
oct | 131220624137 |
9 | 33833672147 |
10 | 11983333471 |
11 | 509a30888a |
12 | 23a523b567 |
13 | 118c87a785 |
14 | 81972006b |
15 | 4a207c4d1 |
hex | 2ca43285f |
11983333471 has 4 divisors (see below), whose sum is σ = 11983883472. Its totient is φ = 11982783472.
The previous prime is 11983333447. The next prime is 11983333489. The reversal of 11983333471 is 17433338911.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11983333471 is a prime.
It is a super-3 number, since 3×119833334713 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11983333771) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 240910 + ... + 286363.
It is an arithmetic number, because the mean of its divisors is an integer number (2995970868).
Almost surely, 211983333471 is an apocalyptic number.
11983333471 is a deficient number, since it is larger than the sum of its proper divisors (550001).
11983333471 is an equidigital number, since it uses as much as digits as its factorization.
11983333471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 550000.
The product of its digits is 163296, while the sum is 43.
The spelling of 11983333471 in words is "eleven billion, nine hundred eighty-three million, three hundred thirty-three thousand, four hundred seventy-one".
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