Base | Representation |
---|---|
bin | 110111110011111000… |
… | …1101111101001101001 |
3 | 102110100201222200211011 |
4 | 1233213301233221221 |
5 | 3430424242202441 |
6 | 131020511103521 |
7 | 11442030043126 |
oct | 1574761575151 |
9 | 373321880734 |
10 | 119852694121 |
11 | 469137a3026 |
12 | 1b28a511ba1 |
13 | b3c081c824 |
14 | 5b2d95d74d |
15 | 31b70a9581 |
hex | 1be7c6fa69 |
119852694121 has 2 divisors, whose sum is σ = 119852694122. Its totient is φ = 119852694120.
The previous prime is 119852694119. The next prime is 119852694133. The reversal of 119852694121 is 121496258911.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 119758215721 + 94478400 = 346061^2 + 9720^2 .
It is a cyclic number.
It is not a de Polignac number, because 119852694121 - 21 = 119852694119 is a prime.
Together with 119852694119, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (119852694191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59926347060 + 59926347061.
It is an arithmetic number, because the mean of its divisors is an integer number (59926347061).
Almost surely, 2119852694121 is an apocalyptic number.
It is an amenable number.
119852694121 is a deficient number, since it is larger than the sum of its proper divisors (1).
119852694121 is an equidigital number, since it uses as much as digits as its factorization.
119852694121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 311040, while the sum is 49.
The spelling of 119852694121 in words is "one hundred nineteen billion, eight hundred fifty-two million, six hundred ninety-four thousand, one hundred twenty-one".
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