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119852775384247 is a prime number
BaseRepresentation
bin11011010000000101100110…
…000110100010010010110111
3120201100210221222200122112001
4123100011212012202102313
5111202131440444243442
61102523334354240131
734150035334456153
oct3320054606422267
9521323858618461
10119852775384247
1135209305170354
121153832bb86047
1351b50b6b69419
142184c96136063
15dcc9a454c2b7
hex6d01661a24b7

119852775384247 has 2 divisors, whose sum is σ = 119852775384248. Its totient is φ = 119852775384246.

The previous prime is 119852775384233. The next prime is 119852775384269. The reversal of 119852775384247 is 742483577258911.

It is a weak prime.

It is an emirp because it is prime and its reverse (742483577258911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 119852775384247 - 231 = 119850627900599 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 119852775384247.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119852775384217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59926387692123 + 59926387692124.

It is an arithmetic number, because the mean of its divisors is an integer number (59926387692124).

Almost surely, 2119852775384247 is an apocalyptic number.

119852775384247 is a deficient number, since it is larger than the sum of its proper divisors (1).

119852775384247 is an equidigital number, since it uses as much as digits as its factorization.

119852775384247 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 948326400, while the sum is 73.

The spelling of 119852775384247 in words is "one hundred nineteen trillion, eight hundred fifty-two billion, seven hundred seventy-five million, three hundred eighty-four thousand, two hundred forty-seven".