1198830002609 has 2 divisors, whose sum is σ = 1198830002610. Its totient is φ = 1198830002608.

The previous prime is 1198830002569. The next prime is 1198830002611. The reversal of 1198830002609 is 9062000388911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 901935788209 + 296894214400 = 949703^2 + 544880^2 .

It is a cyclic number.

It is not a de Polignac number, because 1198830002609 - 2⁸ = 1198830002353 is a prime.

Together with 1198830002611, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1198830002659) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 599415001304 + 599415001305.

It is an arithmetic number, because the mean of its divisors is an integer number (599415001305).

Almost surely, 2^{1198830002609} is an apocalyptic number.

It is an amenable number.

1198830002609 is a deficient number, since it is larger than the sum of its proper divisors (1).

1198830002609 is an equidigital number, since it uses as much as digits as its factorization.

1198830002609 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 186624, while the sum is 47.

The spelling of 1198830002609 in words is "one trillion, one hundred ninety-eight billion, eight hundred thirty million, two thousand, six hundred nine".