11991111103 has 2 divisors, whose sum is σ = 11991111104. Its totient is φ = 11991111102.

The previous prime is 11991111091. The next prime is 11991111149. The reversal of 11991111103 is 30111119911.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11991111103 - 2²⁵ = 11957556671 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11991111703) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5995555551 + 5995555552.

It is an arithmetic number, because the mean of its divisors is an integer number (5995555552).

Almost surely, 2^11991111103 is an apocalyptic number.

11991111103 is a deficient number, since it is larger than the sum of its proper divisors (1).

11991111103 is an equidigital number, since it uses as much as digits as its factorization.

11991111103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 28.

The spelling of 11991111103 in words is "eleven billion, nine hundred ninety-one million, one hundred eleven thousand, one hundred three".