11992554281 has 2 divisors, whose sum is σ = 11992554282. Its totient is φ = 11992554280.

The previous prime is 11992554257. The next prime is 11992554283. The reversal of 11992554281 is 18245529911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10444840000 + 1547714281 = 102200^2 + 39341^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11992554281 is a prime.

It is a super-2 number, since 2×11992554281² (a number of 21 digits) contains 22 as substring.

Together with 11992554283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11992554283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5996277140 + 5996277141.

It is an arithmetic number, because the mean of its divisors is an integer number (5996277141).

Almost surely, 2^11992554281 is an apocalyptic number.

It is an amenable number.

11992554281 is a deficient number, since it is larger than the sum of its proper divisors (1).

11992554281 is an equidigital number, since it uses as much as digits as its factorization.

11992554281 is an evil number, because the sum of its binary digits is even.

The product of its digits is 259200, while the sum is 47.

The spelling of 11992554281 in words is "eleven billion, nine hundred ninety-two million, five hundred fifty-four thousand, two hundred eighty-one".