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11993904449 is a prime number
BaseRepresentation
bin10110010101110010…
…00111010101000001
31010221212122110211022
423022321013111001
5144030414420244
65302050555225
7603135335312
oct131271072501
933855573738
1011993904449
1150a5278a2a
1223a8898b15
131191b0c1a7
1481acb2609
154a2e696ee
hex2cae47541

11993904449 has 2 divisors, whose sum is σ = 11993904450. Its totient is φ = 11993904448.

The previous prime is 11993904427. The next prime is 11993904521. The reversal of 11993904449 is 94440939911.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11889721600 + 104182849 = 109040^2 + 10207^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11993904449 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11993904449.

It is not a weakly prime, because it can be changed into another prime (11993904049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5996952224 + 5996952225.

It is an arithmetic number, because the mean of its divisors is an integer number (5996952225).

Almost surely, 211993904449 is an apocalyptic number.

It is an amenable number.

11993904449 is a deficient number, since it is larger than the sum of its proper divisors (1).

11993904449 is an equidigital number, since it uses as much as digits as its factorization.

11993904449 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1259712, while the sum is 53.

The spelling of 11993904449 in words is "eleven billion, nine hundred ninety-three million, nine hundred four thousand, four hundred forty-nine".