Base | Representation |
---|---|
bin | 11011010001011010110111… |
… | …011000110101101010110111 |
3 | 120201200120021211100021221002 |
4 | 123101122313120311222313 |
5 | 111210131443330344121 |
6 | 1103033355513313515 |
7 | 34156456253260205 |
oct | 3321326730655267 |
9 | 521616254307832 |
10 | 119944333449911 |
11 | 35244119321213 |
12 | 1155202270589b |
13 | 51c0918701339 |
14 | 218949dd30075 |
15 | dd0062592e0b |
hex | 6d16b7635ab7 |
119944333449911 has 2 divisors, whose sum is σ = 119944333449912. Its totient is φ = 119944333449910.
The previous prime is 119944333449907. The next prime is 119944333449923.
119944333449911 is nontrivially palindromic in base 10.
It is a weak prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 119944333449911 - 22 = 119944333449907 is a prime.
It is a super-2 number, since 2×1199443334499112 (a number of 29 digits) contains 22 as substring.
It is a zygodrome in base 10.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (119944333443911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59972166724955 + 59972166724956.
It is an arithmetic number, because the mean of its divisors is an integer number (59972166724956).
Almost surely, 2119944333449911 is an apocalyptic number.
119944333449911 is a deficient number, since it is larger than the sum of its proper divisors (1).
119944333449911 is an equidigital number, since it uses as much as digits as its factorization.
119944333449911 is an evil number, because the sum of its binary digits is even.
The product of its digits is 45349632, while the sum is 65.
The spelling of 119944333449911 in words is "one hundred nineteen trillion, nine hundred forty-four billion, three hundred thirty-three million, four hundred forty-nine thousand, nine hundred eleven".
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