Base | Representation |
---|---|
bin | 1010111010010100010100… |
… | …1110010101010000011101 |
3 | 1120110220100220112111202122 |
4 | 2232211011032111100131 |
5 | 3033024331242331332 |
6 | 41303203101432325 |
7 | 2345516653211432 |
oct | 256450516252035 |
9 | 46426326474678 |
10 | 11997005042717 |
11 | 39059a06490a2 |
12 | 141912486b6a5 |
13 | 69040b082706 |
14 | 2d692dd29b89 |
15 | 15c10a025c12 |
hex | ae94539541d |
11997005042717 has 2 divisors, whose sum is σ = 11997005042718. Its totient is φ = 11997005042716.
The previous prime is 11997005042713. The next prime is 11997005042749. The reversal of 11997005042717 is 71724050079911.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10497509280196 + 1499495762521 = 3239986^2 + 1224539^2 .
It is a cyclic number.
It is not a de Polignac number, because 11997005042717 - 22 = 11997005042713 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11997005042713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5998502521358 + 5998502521359.
It is an arithmetic number, because the mean of its divisors is an integer number (5998502521359).
Almost surely, 211997005042717 is an apocalyptic number.
It is an amenable number.
11997005042717 is a deficient number, since it is larger than the sum of its proper divisors (1).
11997005042717 is an equidigital number, since it uses as much as digits as its factorization.
11997005042717 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1111320, while the sum is 53.
The spelling of 11997005042717 in words is "eleven trillion, nine hundred ninety-seven billion, five million, forty-two thousand, seven hundred seventeen".
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