Base | Representation |
---|---|
bin | 1010111010011111110111… |
… | …0001010100011011010111 |
3 | 1120111012100200112201102020 |
4 | 2232213331301110123113 |
5 | 3033102201403101403 |
6 | 41304434223344223 |
7 | 2345656460254461 |
oct | 256477561243327 |
9 | 46435320481366 |
10 | 12000101222103 |
11 | 390723a330535 |
12 | 1419849752073 |
13 | 6907b2670717 |
14 | 2d6b4520b131 |
15 | 15c23bc67453 |
hex | ae9fdc546d7 |
12000101222103 has 8 divisors (see below), whose sum is σ = 16028156217216. Its totient is φ = 7986056854200.
The previous prime is 12000101222071. The next prime is 12000101222159. The reversal of 12000101222103 is 30122210100021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12000101222103 - 25 = 12000101222071 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12000101226103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3502654803 + ... + 3502658228.
It is an arithmetic number, because the mean of its divisors is an integer number (2003519527152).
Almost surely, 212000101222103 is an apocalyptic number.
12000101222103 is a deficient number, since it is larger than the sum of its proper divisors (4028054995113).
12000101222103 is an equidigital number, since it uses as much as digits as its factorization.
12000101222103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7005313605.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 12000101222103 its reverse (30122210100021), we get a palindrome (42122311322124).
The spelling of 12000101222103 in words is "twelve trillion, one hundred one million, two hundred twenty-two thousand, one hundred three".
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