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12000113711413 is a prime number
BaseRepresentation
bin1010111010011111111010…
…0000111101100100110101
31120111012101120001020112021
42232213332200331210311
53033102213102231123
641304435351153141
72345660001362452
oct256477640754465
946435346036467
1012000113711413
113907246390983
1214198519757b1
136907b5124349
142d6b46b3c829
1515c23cdd2c5d
hexae9fe83d935

12000113711413 has 2 divisors, whose sum is σ = 12000113711414. Its totient is φ = 12000113711412.

The previous prime is 12000113711347. The next prime is 12000113711441. The reversal of 12000113711413 is 31411731100021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11900243806929 + 99869904484 = 3449673^2 + 316022^2 .

It is a cyclic number.

It is not a de Polignac number, because 12000113711413 - 221 = 12000111614261 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12000113711483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000056855706 + 6000056855707.

It is an arithmetic number, because the mean of its divisors is an integer number (6000056855707).

Almost surely, 212000113711413 is an apocalyptic number.

It is an amenable number.

12000113711413 is a deficient number, since it is larger than the sum of its proper divisors (1).

12000113711413 is an equidigital number, since it uses as much as digits as its factorization.

12000113711413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 12000113711413 its reverse (31411731100021), we get a palindrome (43411844811434).

The spelling of 12000113711413 in words is "twelve trillion, one hundred thirteen million, seven hundred eleven thousand, four hundred thirteen".