Base | Representation |
---|---|
bin | 11011010010001111110110… |
… | …110000111101000111100011 |
3 | 120201220000011010201010112211 |
4 | 123102033312300331013203 |
5 | 111212100010203430311 |
6 | 1103115445444102551 |
7 | 34163542244152126 |
oct | 3322176660750743 |
9 | 521800133633484 |
10 | 120001231311331 |
11 | 35266266716687 |
12 | 11561061694a57 |
13 | 51c60b5564c66 |
14 | 218c13a7d03bd |
15 | dd17927c8821 |
hex | 6d23f6c3d1e3 |
120001231311331 has 2 divisors, whose sum is σ = 120001231311332. Its totient is φ = 120001231311330.
The previous prime is 120001231311323. The next prime is 120001231311359. The reversal of 120001231311331 is 133113132100021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120001231311331 - 23 = 120001231311323 is a prime.
It is a super-2 number, since 2×1200012313113312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120001231311301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60000615655665 + 60000615655666.
It is an arithmetic number, because the mean of its divisors is an integer number (60000615655666).
Almost surely, 2120001231311331 is an apocalyptic number.
120001231311331 is a deficient number, since it is larger than the sum of its proper divisors (1).
120001231311331 is an equidigital number, since it uses as much as digits as its factorization.
120001231311331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 120001231311331 its reverse (133113132100021), we get a palindrome (253114363411352).
The spelling of 120001231311331 in words is "one hundred twenty trillion, one billion, two hundred thirty-one million, three hundred eleven thousand, three hundred thirty-one".
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