120001323013303 has 4 divisors (see below), whose sum is σ = 120005826410800. Its totient is φ = 119996819615808.

The previous prime is 120001323013289. The next prime is 120001323013309. The reversal of 120001323013303 is 303310323100021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120001323013303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120001323013309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2251658778 + ... + 2251712071.

It is an arithmetic number, because the mean of its divisors is an integer number (30001456602700).

Almost surely, 2^{120001323013303} is an apocalyptic number.

120001323013303 is a deficient number, since it is larger than the sum of its proper divisors (4503397497).

120001323013303 is an equidigital number, since it uses as much as digits as its factorization.

120001323013303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4503397496.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 120001323013303 its reverse (303310323100021), we get a palindrome (423311646113324).

The spelling of 120001323013303 in words is "one hundred twenty trillion, one billion, three hundred twenty-three million, thirteen thousand, three hundred three".