Base | Representation |
---|---|
bin | 1010111010100000000001… |
… | …0001000010111001100011 |
3 | 1120111012110121022222222001 |
4 | 2232220000101002321203 |
5 | 3033102243112441342 |
6 | 41304442321024431 |
7 | 2345660506205203 |
oct | 256500021027143 |
9 | 46435417288861 |
10 | 12000143093347 |
11 | 3907260a29a72 |
12 | 141985b785117 |
13 | 6907bb240bc6 |
14 | 2d6b4a9ca403 |
15 | 15c2407888b7 |
hex | aea00442e63 |
12000143093347 has 2 divisors, whose sum is σ = 12000143093348. Its totient is φ = 12000143093346.
The previous prime is 12000143093339. The next prime is 12000143093353. The reversal of 12000143093347 is 74339034100021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12000143093347 - 23 = 12000143093339 is a prime.
It is not a weakly prime, because it can be changed into another prime (12000143093357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000071546673 + 6000071546674.
It is an arithmetic number, because the mean of its divisors is an integer number (6000071546674).
Almost surely, 212000143093347 is an apocalyptic number.
12000143093347 is a deficient number, since it is larger than the sum of its proper divisors (1).
12000143093347 is an equidigital number, since it uses as much as digits as its factorization.
12000143093347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 37.
Adding to 12000143093347 its reverse (74339034100021), we get a palindrome (86339177193368).
The spelling of 12000143093347 in words is "twelve trillion, one hundred forty-three million, ninety-three thousand, three hundred forty-seven".
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