Base | Representation |
---|---|
bin | 10110010110100001… |
… | …11100001011101111 |
3 | 1010222022101210110110 |
4 | 23023100330023233 |
5 | 144034014302010 |
6 | 5302432511103 |
7 | 603242410542 |
oct | 131320741357 |
9 | 33868353413 |
10 | 12000150255 |
11 | 50a8854555 |
12 | 23aa9ab493 |
13 | 11931b8032 |
14 | 81ba5a859 |
15 | 4a37a0120 |
hex | 2cb43c2ef |
12000150255 has 32 divisors (see below), whose sum is σ = 19289456640. Its totient is φ = 6370415360.
The previous prime is 12000150221. The next prime is 12000150263. The reversal of 12000150255 is 55205100021.
It is not a de Polignac number, because 12000150255 - 26 = 12000150191 is a prime.
It is a super-3 number, since 3×120001502553 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3267070 + ... + 3270740.
It is an arithmetic number, because the mean of its divisors is an integer number (602795520).
Almost surely, 212000150255 is an apocalyptic number.
12000150255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12000150255 is a deficient number, since it is larger than the sum of its proper divisors (7289306385).
12000150255 is a wasteful number, since it uses less digits than its factorization.
12000150255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4631.
The product of its (nonzero) digits is 500, while the sum is 21.
Adding to 12000150255 its reverse (55205100021), we get a palindrome (67205250276).
The spelling of 12000150255 in words is "twelve billion, one hundred fifty thousand, two hundred fifty-five".
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