12000200230313 has 4 divisors (see below), whose sum is σ = 12000228422400. Its totient is φ = 12000172038228.

The previous prime is 12000200230259. The next prime is 12000200230327. The reversal of 12000200230313 is 31303200200021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12000200230313 - 2²⁸ = 11999931794857 is a prime.

It is a super-3 number, since 3×12000200230313³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12000200230291 and 12000200230300.

It is not an unprimeable number, because it can be changed into a prime (12000200236313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13447613 + ... + 14312186.

It is an arithmetic number, because the mean of its divisors is an integer number (3000057105600).

Almost surely, 2^{12000200230313} is an apocalyptic number.

It is an amenable number.

12000200230313 is a deficient number, since it is larger than the sum of its proper divisors (28192087).

12000200230313 is an equidigital number, since it uses as much as digits as its factorization.

12000200230313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28192086.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 12000200230313 its reverse (31303200200021), we get a palindrome (43303400430334).

The spelling of 12000200230313 in words is "twelve trillion, two hundred million, two hundred thirty thousand, three hundred thirteen".