120002012200211 has 4 divisors (see below), whose sum is σ = 120014728328352. Its totient is φ = 119989296072072.

The previous prime is 120002012200201. The next prime is 120002012200229. The reversal of 120002012200211 is 112002210200021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120002012200211 is a prime.

It is a super-3 number, since 3×120002012200211³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120002012200201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6358049915 + ... + 6358068788.

It is an arithmetic number, because the mean of its divisors is an integer number (30003682082088).

Almost surely, 2^{120002012200211} is an apocalyptic number.

120002012200211 is a deficient number, since it is larger than the sum of its proper divisors (12716128141).

120002012200211 is an equidigital number, since it uses as much as digits as its factorization.

120002012200211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12716128140.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 120002012200211 its reverse (112002210200021), we get a palindrome (232004222400232).

The spelling of 120002012200211 in words is "one hundred twenty trillion, two billion, twelve million, two hundred thousand, two hundred eleven".