Base | Representation |
---|---|
bin | 11011010010010000100101… |
… | …111001100100110000100011 |
3 | 120201220002012020201100200011 |
4 | 123102100211321210300203 |
5 | 111212103120124200003 |
6 | 1103120100133305351 |
7 | 34163600655562351 |
oct | 3322204571446043 |
9 | 521802166640604 |
10 | 120002022100003 |
11 | 3526663203593a |
12 | 11561242495257 |
13 | 51c61b0341254 |
14 | 218c1b383c7d1 |
15 | dd17dbe3146d |
hex | 6d2425e64c23 |
120002022100003 has 2 divisors, whose sum is σ = 120002022100004. Its totient is φ = 120002022100002.
The previous prime is 120002022099991. The next prime is 120002022100033. The reversal of 120002022100003 is 300001220200021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120002022100003 is a prime.
It is not a weakly prime, because it can be changed into another prime (120002022100033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60001011050001 + 60001011050002.
It is an arithmetic number, because the mean of its divisors is an integer number (60001011050002).
Almost surely, 2120002022100003 is an apocalyptic number.
120002022100003 is a deficient number, since it is larger than the sum of its proper divisors (1).
120002022100003 is an equidigital number, since it uses as much as digits as its factorization.
120002022100003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 120002022100003 its reverse (300001220200021), we get a palindrome (420003242300024).
The spelling of 120002022100003 in words is "one hundred twenty trillion, two billion, twenty-two million, one hundred thousand, three".
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