Base | Representation |
---|---|
bin | 10001011101100110110… |
… | …110000000101001010001 |
3 | 11020201110112210202211221 |
4 | 101131212312000221101 |
5 | 124130120423410113 |
6 | 2315140541205041 |
7 | 152461434556300 |
oct | 21354666005121 |
9 | 4221415722757 |
10 | 1200021310033 |
11 | 422a20821697 |
12 | 1746a4860781 |
13 | 89213b394b0 |
14 | 4211d2b4437 |
15 | 213369e998d |
hex | 11766d80a51 |
1200021310033 has 12 divisors (see below), whose sum is σ = 1503323400180. Its totient is φ = 949467409632.
The previous prime is 1200021310013. The next prime is 1200021310049. The reversal of 1200021310033 is 3300131200021.
It can be written as a sum of positive squares in 2 ways, for example, as 385421197329 + 814600112704 = 620823^2 + 902552^2 .
It is not a de Polignac number, because 1200021310033 - 25 = 1200021310001 is a prime.
It is a super-2 number, since 2×12000213100332 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1200021309989 and 1200021310016.
It is not an unprimeable number, because it can be changed into a prime (1200021310013) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 941931318 + ... + 941932591.
It is an arithmetic number, because the mean of its divisors is an integer number (125276950015).
Almost surely, 21200021310033 is an apocalyptic number.
1200021310033 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1200021310033 is a deficient number, since it is larger than the sum of its proper divisors (303302090147).
1200021310033 is a wasteful number, since it uses less digits than its factorization.
1200021310033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1883863936 (or 1883863929 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 1200021310033 its reverse (3300131200021), we get a palindrome (4500152510054).
The spelling of 1200021310033 in words is "one trillion, two hundred billion, twenty-one million, three hundred ten thousand, thirty-three".
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