Base | Representation |
---|---|
bin | 11011010010010000110001… |
… | …001110011100011010010011 |
3 | 120201220002200111021101101122 |
4 | 123102100301032130122103 |
5 | 111212104012300321321 |
6 | 1103120131042152455 |
7 | 34163605453663211 |
oct | 3322206116343223 |
9 | 521802614241348 |
10 | 120002212120211 |
11 | 3526671a321933 |
12 | 1156129605272b |
13 | 51c6210812c45 |
14 | 218c1d0b83cb1 |
15 | dd17ed9688ab |
hex | 6d243139c693 |
120002212120211 has 2 divisors, whose sum is σ = 120002212120212. Its totient is φ = 120002212120210.
The previous prime is 120002212120199. The next prime is 120002212120237. The reversal of 120002212120211 is 112021212200021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120002212120211 - 210 = 120002212119187 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 120002212120211.
It is not a weakly prime, because it can be changed into another prime (120002212720211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60001106060105 + 60001106060106.
It is an arithmetic number, because the mean of its divisors is an integer number (60001106060106).
Almost surely, 2120002212120211 is an apocalyptic number.
120002212120211 is a deficient number, since it is larger than the sum of its proper divisors (1).
120002212120211 is an equidigital number, since it uses as much as digits as its factorization.
120002212120211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 120002212120211 its reverse (112021212200021), we get a palindrome (232023424320232).
The spelling of 120002212120211 in words is "one hundred twenty trillion, two billion, two hundred twelve million, one hundred twenty thousand, two hundred eleven".
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