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120002303114 = 260001151557
BaseRepresentation
bin110111111000010110…
…0011101010010001010
3102110202011111121202222
41233300230131102022
53431231042144424
6131043413454042
711445524514011
oct1576054352212
9373664447688
10120002303114
1146990198521
121b310641322
13b415812765
145b45785a78
1531c52ace5e
hex1bf0b1d48a

120002303114 has 4 divisors (see below), whose sum is σ = 180003454674. Its totient is φ = 60001151556.

The previous prime is 120002303111. The next prime is 120002303173. The reversal of 120002303114 is 411303200021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 118107006889 + 1895296225 = 343667^2 + 43535^2 .

It is a junction number, because it is equal to n+sod(n) for n = 120002303092 and 120002303101.

It is not an unprimeable number, because it can be changed into a prime (120002303111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30000575777 + ... + 30000575780.

Almost surely, 2120002303114 is an apocalyptic number.

120002303114 is a deficient number, since it is larger than the sum of its proper divisors (60001151560).

120002303114 is an equidigital number, since it uses as much as digits as its factorization.

120002303114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60001151559.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 120002303114 its reverse (411303200021), we get a palindrome (531305503135).

The spelling of 120002303114 in words is "one hundred twenty billion, two million, three hundred three thousand, one hundred fourteen".

Divisors: 1 2 60001151557 120002303114