Base | Representation |
---|---|
bin | 10001011101100110111… |
… | …101100111001111001001 |
3 | 11020201110200120000211201 |
4 | 101131212331213033021 |
5 | 124130121431144423 |
6 | 2315141052024201 |
7 | 152461460530105 |
oct | 21354675471711 |
9 | 4221420500751 |
10 | 1200023303113 |
11 | 422a21963068 |
12 | 1746a5462061 |
13 | 8921438672b |
14 | 4211d672905 |
15 | 21336c902ad |
hex | 11766f673c9 |
1200023303113 has 2 divisors, whose sum is σ = 1200023303114. Its totient is φ = 1200023303112.
The previous prime is 1200023303081. The next prime is 1200023303117. The reversal of 1200023303113 is 3113033200021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 814248155449 + 385775147664 = 902357^2 + 621108^2 .
It is a cyclic number.
It is not a de Polignac number, because 1200023303113 - 25 = 1200023303081 is a prime.
It is not a weakly prime, because it can be changed into another prime (1200023303117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600011651556 + 600011651557.
It is an arithmetic number, because the mean of its divisors is an integer number (600011651557).
Almost surely, 21200023303113 is an apocalyptic number.
It is an amenable number.
1200023303113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200023303113 is an equidigital number, since it uses as much as digits as its factorization.
1200023303113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 1200023303113 its reverse (3113033200021), we get a palindrome (4313056503134).
The spelling of 1200023303113 in words is "one trillion, two hundred billion, twenty-three million, three hundred three thousand, one hundred thirteen".
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