Base | Representation |
---|---|
bin | 110111111000010110… |
… | …0111111101101100011 |
3 | 102110202011202210012211 |
4 | 1233300230333231203 |
5 | 3431231111203011 |
6 | 131043420502551 |
7 | 11445525642103 |
oct | 1576054775543 |
9 | 373664683184 |
10 | 120002444131 |
11 | 46990284469 |
12 | 1b3106aaa57 |
13 | b4158619bb |
14 | 5b457c1203 |
15 | 31c52d9b21 |
hex | 1bf0b3fb63 |
120002444131 has 2 divisors, whose sum is σ = 120002444132. Its totient is φ = 120002444130.
The previous prime is 120002444101. The next prime is 120002444143. The reversal of 120002444131 is 131444200021.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (131444200021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 120002444131 - 215 = 120002411363 is a prime.
It is a super-2 number, since 2×1200024441312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120002444101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60001222065 + 60001222066.
It is an arithmetic number, because the mean of its divisors is an integer number (60001222066).
Almost surely, 2120002444131 is an apocalyptic number.
120002444131 is a deficient number, since it is larger than the sum of its proper divisors (1).
120002444131 is an equidigital number, since it uses as much as digits as its factorization.
120002444131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 120002444131 its reverse (131444200021), we get a palindrome (251446644152).
The spelling of 120002444131 in words is "one hundred twenty billion, two million, four hundred forty-four thousand, one hundred thirty-one".
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