120003220213 has 4 divisors (see below), whose sum is σ = 121794313120. Its totient is φ = 118212127308.

The previous prime is 120003220187. The next prime is 120003220231. The reversal of 120003220213 is 312022300021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120003220213 is a prime.

It is a super-2 number, since 2×120003220213² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120003220283) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 895546353 + ... + 895546486.

It is an arithmetic number, because the mean of its divisors is an integer number (30448578280).

Almost surely, 2^120003220213 is an apocalyptic number.

It is an amenable number.

120003220213 is a deficient number, since it is larger than the sum of its proper divisors (1791092907).

120003220213 is an equidigital number, since it uses as much as digits as its factorization.

120003220213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1791092906.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 120003220213 its reverse (312022300021), we get a palindrome (432025520234).

The spelling of 120003220213 in words is "one hundred twenty billion, three million, two hundred twenty thousand, two hundred thirteen".