Base | Representation |
---|---|
bin | 110111111000011000… |
… | …0101011100011010011 |
3 | 102110202020120212022121 |
4 | 1233300300223203103 |
5 | 3431231333111011 |
6 | 131043453315111 |
7 | 11445540104323 |
oct | 1576060534323 |
9 | 373666525277 |
10 | 120003410131 |
11 | 46990884210 |
12 | 1b310a95a97 |
13 | b415b0c5b7 |
14 | 5b45993283 |
15 | 31c542ae71 |
hex | 1bf0c2b8d3 |
120003410131 has 16 divisors (see below), whose sum is σ = 131307644160. Its totient is φ = 108765205920.
The previous prime is 120003410129. The next prime is 120003410143. The reversal of 120003410131 is 131014300021.
It is a cyclic number.
It is not a de Polignac number, because 120003410131 - 21 = 120003410129 is a prime.
It is a super-2 number, since 2×1200034101312 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (120003410171) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19436961 + ... + 19443133.
It is an arithmetic number, because the mean of its divisors is an integer number (8206727760).
Almost surely, 2120003410131 is an apocalyptic number.
120003410131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
120003410131 is a deficient number, since it is larger than the sum of its proper divisors (11304234029).
120003410131 is a wasteful number, since it uses less digits than its factorization.
120003410131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11226.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 120003410131 its reverse (131014300021), we get a palindrome (251017710152).
The spelling of 120003410131 in words is "one hundred twenty billion, three million, four hundred ten thousand, one hundred thirty-one".
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