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120003410131 = 1137946636173
BaseRepresentation
bin110111111000011000…
…0101011100011010011
3102110202020120212022121
41233300300223203103
53431231333111011
6131043453315111
711445540104323
oct1576060534323
9373666525277
10120003410131
1146990884210
121b310a95a97
13b415b0c5b7
145b45993283
1531c542ae71
hex1bf0c2b8d3

120003410131 has 16 divisors (see below), whose sum is σ = 131307644160. Its totient is φ = 108765205920.

The previous prime is 120003410129. The next prime is 120003410143. The reversal of 120003410131 is 131014300021.

It is a cyclic number.

It is not a de Polignac number, because 120003410131 - 21 = 120003410129 is a prime.

It is a super-2 number, since 2×1200034101312 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (120003410171) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19436961 + ... + 19443133.

It is an arithmetic number, because the mean of its divisors is an integer number (8206727760).

Almost surely, 2120003410131 is an apocalyptic number.

120003410131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

120003410131 is a deficient number, since it is larger than the sum of its proper divisors (11304234029).

120003410131 is a wasteful number, since it uses less digits than its factorization.

120003410131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11226.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 120003410131 its reverse (131014300021), we get a palindrome (251017710152).

The spelling of 120003410131 in words is "one hundred twenty billion, three million, four hundred ten thousand, one hundred thirty-one".

Divisors: 1 11 379 4169 4663 6173 51293 67903 1767277 2339567 19440047 25735237 28784699 316631689 10909400921 120003410131