Base | Representation |
---|---|
bin | 10110010110100011… |
… | …01011010110001011 |
3 | 1010222022202121110021 |
4 | 23023101223112023 |
5 | 144034041442220 |
6 | 5302441001311 |
7 | 603244144003 |
oct | 131321532613 |
9 | 33868677407 |
10 | 12000343435 |
11 | 50a8976703 |
12 | 23aaa83237 |
13 | 1193254c42 |
14 | 81baab003 |
15 | 4a37dc4aa |
hex | 2cb46b58b |
12000343435 has 16 divisors (see below), whose sum is σ = 15254381376. Its totient is φ = 9031472128.
The previous prime is 12000343429. The next prime is 12000343451. The reversal of 12000343435 is 53434300021.
It is a cyclic number.
It is not a de Polignac number, because 12000343435 - 29 = 12000342923 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 164514 + ... + 225976.
It is an arithmetic number, because the mean of its divisors is an integer number (953398836).
Almost surely, 212000343435 is an apocalyptic number.
12000343435 is a deficient number, since it is larger than the sum of its proper divisors (3254037941).
12000343435 is a wasteful number, since it uses less digits than its factorization.
12000343435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63782.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 12000343435 its reverse (53434300021), we get a palindrome (65434643456).
The spelling of 12000343435 in words is "twelve billion, three hundred forty-three thousand, four hundred thirty-five".
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