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12000431331 = 3271910025423
BaseRepresentation
bin10110010110100100…
…00000110011100011
31010222022221002000200
423023102000303203
5144034102300311
65302442520243
7603244661160
oct131322006343
933868832020
1012000431331
1150a8a26749
1223aab06083
131193285c55
1481bad1067
154a3808556
hex2cb480ce3

12000431331 has 24 divisors (see below), whose sum is σ = 20852881920. Its totient is φ = 6496473456.

The previous prime is 12000431321. The next prime is 12000431347. The reversal of 12000431331 is 13313400021.

12000431331 is a `hidden beast` number, since 1 + 200 + 0 + 431 + 3 + 31 = 666.

It is not a de Polignac number, because 12000431331 - 27 = 12000431203 is a prime.

It is a super-2 number, since 2×120004313312 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (12000431321) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5011515 + ... + 5013908.

It is an arithmetic number, because the mean of its divisors is an integer number (868870080).

Almost surely, 212000431331 is an apocalyptic number.

12000431331 is a deficient number, since it is larger than the sum of its proper divisors (8852450589).

12000431331 is a wasteful number, since it uses less digits than its factorization.

12000431331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10025455 (or 10025452 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 12000431331 its reverse (13313400021), we get a palindrome (25313831352).

The spelling of 12000431331 in words is "twelve billion, four hundred thirty-one thousand, three hundred thirty-one".

Divisors: 1 3 7 9 19 21 57 63 133 171 399 1197 10025423 30076269 70177961 90228807 190483037 210533883 571449111 631601649 1333381259 1714347333 4000143777 12000431331