1200044113 has 4 divisors (see below), whose sum is σ = 1252219968. Its totient is φ = 1147868260.

The previous prime is 1200044089. The next prime is 1200044117. The reversal of 1200044113 is 3114400021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1200044113 - 2⁹ = 1200043601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1200044117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26087893 + ... + 26087938.

It is an arithmetic number, because the mean of its divisors is an integer number (313054992).

Almost surely, 2^1200044113 is an apocalyptic number.

It is an amenable number.

1200044113 is a deficient number, since it is larger than the sum of its proper divisors (52175855).

1200044113 is an equidigital number, since it uses as much as digits as its factorization.

1200044113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 52175854.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 1200044113 is about 34641.6528618367. The cubic root of 1200044113 is about 1062.6715904279.

Adding to 1200044113 its reverse (3114400021), we get a palindrome (4314444134).

The spelling of 1200044113 in words is "one billion, two hundred million, forty-four thousand, one hundred thirteen".