120009000143 has 2 divisors, whose sum is σ = 120009000144. Its totient is φ = 120009000142.

The previous prime is 120009000079. The next prime is 120009000179. The reversal of 120009000143 is 341000900021.

It is a strong prime.

It is an emirp because it is prime and its reverse (341000900021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120009000143 - 2⁶ = 120009000079 is a prime.

It is a super-3 number, since 3×120009000143³ (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120009000343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60004500071 + 60004500072.

It is an arithmetic number, because the mean of its divisors is an integer number (60004500072).

Almost surely, 2^120009000143 is an apocalyptic number.

120009000143 is a deficient number, since it is larger than the sum of its proper divisors (1).

120009000143 is an equidigital number, since it uses as much as digits as its factorization.

120009000143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 120009000143 its reverse (341000900021), we get a palindrome (461009900164).

The spelling of 120009000143 in words is "one hundred twenty billion, nine million, one hundred forty-three", and thus it is an aban number.