1200099133 has 2 divisors, whose sum is σ = 1200099134. Its totient is φ = 1200099132.

The previous prime is 1200099101. The next prime is 1200099143. The reversal of 1200099133 is 3319900021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1187009209 + 13089924 = 34453^2 + 3618^2 .

It is a cyclic number.

It is not a de Polignac number, because 1200099133 - 2⁵ = 1200099101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1200099143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600049566 + 600049567.

It is an arithmetic number, because the mean of its divisors is an integer number (600049567).

Almost surely, 2^1200099133 is an apocalyptic number.

It is an amenable number.

1200099133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200099133 is an equidigital number, since it uses as much as digits as its factorization.

1200099133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 28.

The square root of 1200099133 is about 34642.4469834335. The cubic root of 1200099133 is about 1062.6878307468.

Adding to 1200099133 its reverse (3319900021), we get a palindrome (4519999154).

The spelling of 1200099133 in words is "one billion, two hundred million, ninety-nine thousand, one hundred thirty-three".