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12001009995617 is a prime number
BaseRepresentation
bin1010111010100011001111…
…1100000000111101100001
31120111021201000120012022112
42232220303330000331201
53033111032024324432
641305104325445105
72346021133564106
oct256506374007541
946437630505275
1012001009995617
113907666305525
121419a61b70795
136908c8a19626
142d6bcdbacaad
1515c2919287b2
hexaea33f00f61

12001009995617 has 2 divisors, whose sum is σ = 12001009995618. Its totient is φ = 12001009995616.

The previous prime is 12001009995431. The next prime is 12001009995619. The reversal of 12001009995617 is 71659990010021.

12001009995617 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10240614409216 + 1760395586401 = 3200096^2 + 1326799^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12001009995617 is a prime.

Together with 12001009995619, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12001009995619) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000504997808 + 6000504997809.

It is an arithmetic number, because the mean of its divisors is an integer number (6000504997809).

Almost surely, 212001009995617 is an apocalyptic number.

It is an amenable number.

12001009995617 is a deficient number, since it is larger than the sum of its proper divisors (1).

12001009995617 is an equidigital number, since it uses as much as digits as its factorization.

12001009995617 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 306180, while the sum is 50.

The spelling of 12001009995617 in words is "twelve trillion, one billion, nine million, nine hundred ninety-five thousand, six hundred seventeen".