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1200112112113 is a prime number
BaseRepresentation
bin10001011101101100010…
…000011001000111110001
311020201200212122222212221
4101131230100121013301
5124130312200041423
62315153543321041
7152463616432345
oct21355420310761
94221625588787
101200112112113
11422a68000632
1217470b150181
13892298ac535
144212b38d625
152133e983e5d
hex1176c4191f1

1200112112113 has 2 divisors, whose sum is σ = 1200112112114. Its totient is φ = 1200112112112.

The previous prime is 1200112112099. The next prime is 1200112112141. The reversal of 1200112112113 is 3112112110021.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 836681578209 + 363430533904 = 914703^2 + 602852^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1200112112113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1200112112513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600056056056 + 600056056057.

It is an arithmetic number, because the mean of its divisors is an integer number (600056056057).

Almost surely, 21200112112113 is an apocalyptic number.

It is an amenable number.

1200112112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200112112113 is an equidigital number, since it uses as much as digits as its factorization.

1200112112113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 1200112112113 its reverse (3112112110021), we get a palindrome (4312224222134).

The spelling of 1200112112113 in words is "one trillion, two hundred billion, one hundred twelve million, one hundred twelve thousand, one hundred thirteen".